[truye^.n] Mo^.t Truye^.n Ddu`a Nho Nho? (Part I)

[VietHai.Nguyen@di.epfl.ch (Viet Hai NGUYEN)]

                   MO^.T TRUYE^.N DDU`A NHO NHO?

                           -- Tchekhov --


Mo^.t buo^?i tru+a mu`a ddo^ng trong sa'ng... Tro+`i gia' la.nh, re't
co'ng. Nadia khoa'c tay to^i\. Nhu+~ng ha.t bu.i tuye^'t nho+` tra('ng
xo'a ba'm le^n ma^'y mo'n to'c xoa('n vo`ng ru? hai be^n be^n tha'i
du+o+ng na`ng, le^n ha`ng lo^ng to+ mi.n phi'a tre^n mo^i. Na`ng va`
to^i ddu+'ng tre^n mo^.t ngo.n ddo^`i cao\. Tu+` cho^~ chu'ng to^i
ddu+'ng, su+o+`n ddo^`i ddo^? da`i thoai thoa?i xuo^'ng la^'p loa'ng
du+o+'i a'nh sa'ng nhu+ mo^.t ta^'m gu+o+ng. Be^n ca.nh chu'ng to^i la`
mo^.t chie^'c xe tru+o+.t tuye^'t nho? bo.c mo^.t lo+'p da. ma`u ddo?
tu+o+i\.


- Chu'ng ta cu`ng truo+.t xuo^'ng duo+'i ddi, Nadia - to^i van na`i
na`ng. - Mo^.t la^`n tho^i! To^i cam ddoan vo+'i co^ la` chu'ng ta se~
cha(?ng he^` gi` dda^u\.


Nhu+ng Nadia so+. Ca? ca'i khoa?ng kho^ng gian t+` ddo^i gia`y cao su
nho? nha('n cu?a na`ng dde^'n cha^n qua? ddo^`i phu? ba(ng na`y ddo^'i
vo+'i na`ng tha^.t la` ghe^ so+. Tu+o+?ng nhu+ mo^.t vu+.c sa^u vo^
ta^.n Dddu+'ng dda^y, na`ng chi? mo+'i ddu+a ma('t nhi`n xuo^'ng
du+o+'i, hay to^i chi? mo+'i go+.i y' ba?o na`ng ngo^`i va`o xe
tru+o+.t tuye^'t la` na`ng dda~ so+. he^'t ho^`n, kho^ng tho+? ddu+o+.c
nu+~a, huo^'ng ho^` ne^'u na`ng lie^`u ma.ng lao suo^'ng ca'i vu+.c
sa^u kia thi` kho^ng bie^'t ro^`i ra sao! Na`ng se~ che^'t ma^'t, na`ng
se~ dde^'n pha't ddie^n ma^'t.


- Ta tru+o+.t ddi co^ - To^i co^ na`i - Vie^.c gi` ma` so+. ! Co^ pha?i
bie^'t so+. the^' la` nha't gan, xoa`ng la('m co^ a. !


Cuo^'i cu`ng Nadia cu~ng u+ng thua^.n, nhu+ng qua ne't ma(.t na`ng,
to^i bie^'t ra(`ng tuy va^.y na`ng va^~n so+. che^'t. To^i ddo+~ na`ng
ngo^`i va`o xe tru+o+.t; na`ng run ra^?y, gu+o+ng ma(.t na`ng ta'i
nho+.t. To^i vo`ng tay qua giu+~ la^'y Nadia va` cu`ng nhau lao xuo^'ng
thung lu~ng sa^u tha(?m.


Chie^'c xe lao vu't ddi nhu+ mo^.t vie^n dda.n. La`n kho^ng khi' bi.
xe' qua^.t va`o ma(.t, ga`o ri't be^n tai, dda^m va`o da buo^'t nho'i,
gio' nhu+ muo^'n gia^.t pha(ng dda^`u ra kho?i vai\. Gio' e'p qua'
ma.nh, dde^'n no^~i kho^ng tho+? ddu+o+.c. Tu+o+?ng chu+`ng nhu+ co'
mo^.t con qui? na`o ddang gio+ tay na('m la^'y chu'ng to^i va` vu+`a
ru' le^n vu+`a ke'o chu'ng to^i xuo^ng ddi.a ngu.c. Mo.i va^.t chung
quanh nha^.p la.i tha`nh mo^.t ve^.t da`i lao vun vu't ve^` phi'a
sau\... Chi? mo^.t gia^y la't nu+~a tho^i la` chu'ng to^i se~ che^'t !


- Nadia, anh ye^u em ! - To^i thi` tha`o no'i\.


Chiec xe tru+o+.t dan dan chay cham la.i, tieng gio' ga`o va` tieng dde^'
xe ri't lu'c na`y kho^ng co`n dda'ng ghe^ so+. nhu+ lu'c truoc nu+~a,
ngu+.c dda~ tha^'y de^~ tho+?, va` the^' la` chu'ng to^i dda~ xuo^'ng
dde^'n thung lu~ng. Nadia so+. tu+o+/ng che^'t ddi ddu+o+.c, gu+o+ng
ma(.t na`ng ta'i ha(?n ddi; na`ng tho+? kho^ng ra ho+i\. To^i ddo+~
na`ng ddu+'ng da^.y\.


- Ca'c va`ng to^i cu~ng kho^ng tru+o+.t la^`n nu+~a ! na`ng no'i va`
ddu+a ca(.p ma('t mo+? to dda^`y so+. ha~i nhi`n to^i\. - ... Ca'c
va`ng to^i cu~ng chi.u ! Chi? thie^'u chu't nu+~a la` to^i che^'t !


Mo^.t cho^'c sau, na`ng da^`n da^`n he^'t so+. va` dda~ ba('t dda^`u
nhi`n to^i vo+'i ve? do` xe't : co' pha?i to^i dda~ no'i bo^'n tie^'ng
a^'y, hay chi? la` trong tie^'ng gio' ga`o ri't na`ng nghe thay nhu+
va^.y ? Co`n to^i, toi ddu+'ng be^n ca.nh na`ng, la^'y thuo^'c la' ra
hu't va` cha(m chu' nhi`n chie^'c ga(ng tay cu?a mi`nh.


Na`ng khoa'c tay to^i va` chu'ng to^i cu`ng nhau da.o cho+i mo^.t lu'c
la^u be^n ddo^`i tuyet. Hi`nh nhu+ ddie^`u bi' a^?n la`m na`ng tha^'y
trong lo`ng ba(n khoa(n. Co' ai no'i ra nhu+~ng lo+`i no'i ddo' kho^ng ?


Co' nhung lo+`i no'i ddo' hay kho^ng ? Co' hay kho^ng ? Ddo' la` mo^.t
ca^u ho?i cu?a lo`ng tu+. tro.ng, cu?a danh du+., cu?a cuo^.c ddo+`i
va` nie^`m ha.nh phu'c - mo^.t ca^u ho?i ra^'t he^. tro.ng, he^.
tro.ng nha^'t tre^n ddo+`i na`y\. Nadia dda(m dda(m nhi`n to^i ba(`ng
ca(.p ma('t buo^`n ra^`u no^n no'ng bo^`n cho^`n. Na`ng cha^.m ra~i do
du+. tra? lo+`i nhu+~ng ca^u ho?i cu?a to^i nhu+ cho+` mong to^i se~
tu+. no'i ra ca'i ddie^`u bi' a^?n a^'y. O^I, KHUO^N MA(.T NA`NG LU'C
A^'Y DDA'NG YE^U BIE^'T BAO, Y' NHI. BIE^'T BAO ! To^i tha^'y ro~ na`ng
ddang tu+. day du+'t vo+'i mi`nh, na`ng ca^`n no'i mo^.t ddie^`u gi`,
ca^`n ho?i mo^.t ddie^`u gi`nhu+ng na`ng kho^ng ti`m ddu+o+.c lo+`i, na`ng
ca?m tha^'y ru.t re` kinh so+., mo^.t nie^`m vui na`o ddang nga(n tro+?
na`ng no'i ...


- Na`y anh... - Na`ng no'i, ma('t kho^ng nh`n to^i\.

- Ca'i gi` va^.y ? To^i ho?i\.

- Chu'ng ta cu`ng nhau ... lao do^'c la^`n nu+~a ddi\.


----------------


Chu'ng to^i la^`n theo nhu+~ng ba^.c thang tre`o le^n ddo^`i\. To^i
la.i ddo+~ Nadia le^n xe, ma(.t na`ng ta'i nho+.t, va` toa`n tha^n run
run. Chu'ng to^i la.i lao ve^` phi'a vu+.c tha(?m khu?ng khie^'p va`
gio' la.i ga`o, tie^'ng dde^' xe tru+o+.t la.i ri't le^n. Va` cu~ng
ddu'ng va`o lu'c chie^'c xe lao nhanh nha^'t, tie^'ng gio' ga`o ri't
ghe^ go+'m nha^'t, to^i la.i no'i thi` tha`o

- Nadia, anh ye^u em !

Khi chie^'c xe du+`ng la.i, Nadia vo^.i ddu+a ma('t nhi`n quanh qua?
ddo^`i ma` chu'ng to^i vu+`a tru+o+.t xuo^'ng, ro^`i nhi`n dda(m dda(m va`o
ma(.t to^i, la('ng nghe gio.ng no'i tho+` o+ la~nh dda.m cu?a to^i va`
toa`n tha^n na`ng, ca? tu+` ca'i mu~, ca'i u? tay ba(`ng lo^ng, va`
da'ng ngu+o+`i na`ng nu+~a dde^`u toa't le^n mo^.t ca'i gi` dda^'y ho^`
nghi kho' hie^?u\. Tre^n gu+o+ng ma(.t na`ng nhu+ hie^.n le^n ca'c ca^u
ho?i :

- " Ddie^`u gi` dda~ xa?y ra ? Ai no'i nhu+~ng LO+`I A^'Y ? Anh a^'y
hay chi? la` do ta tu+o+?ng tu+o+.ng ? "


Ddie^`u bi' a^?n a^'y la`m na`ng kho^ng ye^n lo`ng chu't na`o, na`ng kho^ng
chi.u dduo+.c nu+~a\. Co^ be' dda'ng thu+o+ng a^'y kho^ng tra? lo+`i
no^?i nhu+~ng ca^u ho?i, ne't ma(.t na`ng ra^`u ri~ nhu+ muo^'n kho'c.

- Chu'ng ta ve^` nha` tho^i nhe' ? - To^i ho?i\.

- Kho^ng, kho^ng ... to^i thi'ch ... tru+o+.t xe the^' na`y - Na`ng no'i,
ma(.t u+?ng ddo? le^n. - Hay la` chu'ng ta cu`ng nhau tru+o+.t la^`n nu+~a
ddi ?


(co`n tie^'p)