Re:[LIT,SOC]Mie^`n Nam khai pho'ng

[Hong Lam Vu <vuh000@goofy.zdv.Uni-Mainz.de>]

Hi all,

Tui xin phe=92p bi`nh va`i ca^u ve^` ba`i cu?a ba=92c NVKhanh du` ba=92c a^=
=92y
 va(=91ng ma(.t. Bi`nh kho^ng pha?i dde^? khen hay che^ ba'c NVK ma` dde^?
 nha^n dda^y go'p 1 y' kie^'n vo+' ca'c ba'c VNSA nha` ta.

Ba`i "Mie^`n Nam Khai Pho=92ng" te=92 ra "treo dda^`u de^ ba=92n thi.t cho=
=92"
 vi` thu+.c ra ta^.p trung va`o va(n ho.c mie^`n Nam, va` ngoa`i su+.
 khai pho=92ng, co`n kha(?ng ddi.nh ti=92nh tie^`n phong, lo`ng ye^u nu+o+=
=92c cu?a va(n ho.c mie^`n Nam.

Ba`i MNKP ga~i va`o mo^.t va^=92n dde^` sensitive ne^n kho^ng kho?i ga^y tr=
anh ca~i. Tui kho^ng co=92 ddie^`u kie^.n checking out xem ca=92c ba(`ng ch=
u+=92ng cu?a ba=92c NVK chi=92nh xa=92c dde^=92n dda^u ne^n dda`nh gio+=92i=
 ha.n chi? ne^u va`i y=92 kie^=92n chung chung.

Theo tui, mie^`n Nam co=92 mo^.t ba?n sa(=91c va(n ho=92a rie^ng trong to^?=
ng the^? va(n ho=92a VN. Ba`i MNKP dda~ chi? ra pha^`n na`o ca=92i kha=92c =
cu?a va(n ho=92a mie^`n Nam so vo+i mie^`n Ba(=91c. Tui tha^=92y ba=92c NVK=
 muo^=92n du`ng ba`i vie^=92t cu?a mi`nh dde^? qua so=20
sa=92nh 2 ma?ng va(n ho.c mie^`n Nam va` Ba(=92c, chu+=92ng minh ra(`ng mie=
^`n Nam kho^ng ke=92m mie^`n Ba(=91c, tha^.m chi=92 co=92 pha^`n na`o co`n =
ho+n mie^`n Ba(=91c. Pha^`n lo+=92n nha^.n ddi.nh cu?a ba`i vie^=92t ve^` n=
hu+~ng ddie^?m kha=92c giu+~a va(n ho=92a Nam va` Ba(=91
c tu+o+ng ddo^=92i phu` ho+.p vo+=92i nha^.n ddi.nh cu?a tui khi quan sa=92=
t va` so sa=92nh va(n ho=92a 2 mie^`n o+? ca? ca=92c ma?ng ngoa`i va(n ho.c=
=2E

Tuy nhie^n, chu? ddi=92ch chu+=92ng minh su+. kho^ng thua ke=92m cu?a va(n =
ho=92a vu`ng dda^=92t na`y so vo+=92i va(n ho=92a vu`ng dda^=92t kha=92c cu=
~ng "do+?" nhu+ chu? ddi=92ch chu+=92ng minh su+. u+u tu=92 cu?a va(n ho=92=
a 1 vu`ng dda^=92t so vo+=92i va(n ho=92a 1 vu`ng dda^=92t kha=92c
=2E "Do+?" la` vi` no=92 nguy hie^?m va` da.i do^.t. Nguy hie^?m o+? cho^~ =
no=92 de^~ bi. lo+.i du.ng dde^? phu.c vu. cho vie^.c ga^y hie^`m khi=92ch =
giu+~a nguo+`i cu?a 2 mie^`n. Da.i do^.t o+? cho^~ do lo^=92i vie^=92t emot=
ional, no=92 la`m gia?m ti=92nh kha=92ch quan va
` do ddo=92, gia?m su+=92c thuye^=92t phu.c cu?a ca? ba`i vie^=92t.=20

So sa=92nh gio^=92ng kha=92c giu+~a va(n ho.c 2 mie^`n Nam-Ba(=91c la` mo^.=
t vie^.c la`m bo^? i=92ch, nhu+ng ddo`i ho?i pha?i ra^=92t kha=92ch quan. M=
uo^=92n va^.y, pha?i vuo+.t ra kho?i nhu+~ng ca=92i dichotomies mang ti=92n=
h normative. Nguo+`i vie^=92t kho^ng ddu+o+.c khen h
oa(.c che^. Chi? ddu+o+.c la`m co^ng vie^.c so sa=92nh su+. gio^=92ng, kha=
=92c nhau giu+~a hai ddo^=92i tu+o+.ng vo+=92i nhau. Kho^ng ddu+o+.c so chu=
=92ng vo+=92i mo^.t chua^?n mu+.c gia=92 tri. be^n ngoa`i na`o kha=92c, ho`=
ng ke^=92t lua^.n xem ai gia=92 tri. ho+n ai. Co=92 ca?
m tu+o+?ng nhu+ ba`i MNKP cu?a NVKhanh va^~n chu+a thoa=92t kho?i lo^=92i n=
hi`n tho^ng qua la(ng ki=92nh cu?a nhu+~ng normative dichotomies.

Cheers,
La^m.