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Re: [LIT,SOC]Mie^`n Nam khai pho'ng




Hi Anh Tie^'n, anh La^m,

  Ta.i sao la.i kho^ng so sa'nh ddu+o+.c. DDa~ no'i la` va(n ho.c pha'n 
trie^?n thi` pha?i co' u+u tu' hay kho^ng cho+'. Co' no+i co' ne^`n va(n 
ho.c 0 the^' la` dda~ ddo ro^`i.
  Co^' nhie^n ca^n ddo gi` cu~ng pha?i co' go^'c to.a ddo^. Ne^'u anhmang 
gia' tri. o+? toa. ddo^. na`y ra no'i cho ddo^. ddo o+? to.a ddo^. kha'c 
thi` tha^'y du+o+`ng nhu+ kho^ng ddo ddu+o+.c. Hoa(.c la` mang thu+o+'c 
cao su ra ddo.
   To^i thi` ddo ddu+o+.c ra'o ( cho ba?n tha^n to^i tho^i) ke^? ca?
ti`nh ba.n ti`nh ye^u. Ca'i gi` kho^ng ddo ddu+o+.c thi` kho?i ma^'t co^ng
nghi~.
   Co^' nhie^n tru+o+'c khi la^'y tie^u chua^?n ddo, ca^`n xa'c ddi.nh y' 
nghi~a thu+.c tie^~n tru+o+'c dda~: phu.c vu. ai, mu.c ddi'ch gi`.
  
   Ca'i na`y to^i ddo.c tro^.m cu?a cu. Heisenberg, Schrodinger: so^' 
lie^.u ddo phu. thuo^.c va`o tra.ng tha'i rie^ng. Tuy nhie^n cu~ng co`n 
gia' tri. trung bi`nh nu+~a.   

   Cheers
   Aiviet
  

On Tue, 10 Jun 1997, Tran Minh Tien wrote:
 
> To^i kho^ng hie^?u, co' tie^u chua^?n na`o co' the^? so sa'nh su+. ho+n
> ke'm cu?a ne^`n va(n ho.c no'i rie^ng hay va(n ho'a no'i chung ?
> Mo^.t ne^`n va(n ho.c nhu+ the^' na`o thi` ddu+o+.c go.i la` u+u tu' ?
> Va(n ho.c la` va(n ho.c. DDo' kho^ng pha?i la` mie^'ng thi.t hay con
> ca' ngoa`i cho+. dde^? co' the^? ca^n ddong. Ngu+o+`i ta chi? co'
> the^? ti`m ca'c ddie^?m ddo^`ng di. cu?a ca'c ne^`n va(n ho.c hay
> ca'c do`ng va(n ho.c  ma` tho^i\.
> 
> Cheers,
> 
> Tran Minh Tien