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Re: Ba`i Review cu?a TS Nguyen Xuan Tuyen



Hi ca'c ba'c quan ta^m va^'n dde^\ na\y

Tru+o+'c he^'t la\ xin lo^~i ba'c AiViet ho^m tru+o+'c ddo.c bo? so't ca^u
PS cu?a ba'c, sau khi ba'c Tie^'n vie^'t e-mail thi\ mo+'i pha't hie^.n ra.

Thu+' hai la\ ca'm o+n ba'c DV An dda(ng ba\i ba'o le^n. Nhu+~ng tho^ng
tin co\n la.i ba'c co' the^? private mail cho tui ddu+o+.c kho^ng? To^i 
hoa\n toa\n kho^ng lie^n lu.y gi\ dde^'n chuye^.n na\y, chi? muo^'n
co' 1 ca'i nhi\n kha'ch quan tho^i. Merci. 

> > PS: Bo.n My~ cu~ng tha^m, ta.i sao la.i giao VN cho VN. 
> 

Tui thi\ kho^ng cho la\ co' su+. co^' ti\nh cu?a AMS. AMS la\m a(n kha'
"quan lie^u" ho+i dda^u ma\ ngu+o+\i ta cho+i xo? vo+' va^?n ai la\m gi\.
Chuye^.n o^ng Hu+ng review o^ng Tuye^'n thi\ do+n gia?n la\ do cu\ng nga\nh
he.p thi\ de^~ ro+i va\o nhau tho^i. Math reviews ng\ ta pha^n nga\nh
reviewers
(do reviewers tu+. khai khi nha^.n la\m math reviews) ro^\i cu+' khi co'
ba\i dde^'n
thi\ ngu+o+\i ta xa'c ddi.nh xem nga\nh gi\, ro^\i gu+?i cho 1 reviewer
nga\nh
dda^'y mo^.t ca'ch nga^~u nhie^n trong so^' ca'c reviewers "disponible".

> Yes, dda'ng nga.c nhie^n tha^.t\. Ma` cu~ng kho' hie^?u mo^'i
> quan he^. cu?a ma^'y ngu+o+`i na`y: HM-NXT-NHVH. Bie^'t dda^u
> kho^ng co' su+. phu+'c ta.p dda(`ng sau "sa^n kha^'u".
> Be^n Toa'n co' ve?  hay co' "chuye^.n" khi ai ddo' ddu+o+.c
> le^n chu+'c. Ho^`i o^ng DDa`o Tro.ng Thi le^n la`m Hie^.u
> tru+o+?ng  hi`nh nhu+ cu~ng co' xi` xa`o gi` ddo' ve^` ba`i 
> review quye^?n sa'ch gi` ddo'\. 
> 

Chuye^.n co' "quan he^." gi\ giu+~a 3 nha^n va^.t kho^ng thi\ to^i kho^ng
bie^'t,
nhu+ng kho^ng the^? so sa'nh vie^.c na\y vo+'i chuye^.n cu?a o^ng Thi, va\
cu~ng kho^ng the^? vi\ the^' ma\ ke^'t lua^.n la\ gio+'i toa'n "la('m
chuye^.n".

Vie^.c ve^\ o^ng Thi thi\ to^i ho^\i ddo' co' quan ta^m va\ bie^'t kha' ro~
(tui 
cu~ng co' ddo.c quye^?n sa'ch cu?a o^ng Thi). O^ng Thi co' "ke^'t qua?
chi'nh"
(ca'i ma\ ba'c Ha\m Cha^u go.i la\ gia?i ba\i toa'n the^' ky? y' ma\)
chu+'ng
minh bi. ho^?ng tha^.t (co' nghia~ la\ "ddi.nh ly'" chu+a bie^'t ddu'ng hay
sai), tuy
nhie^n trong khoa ho.c la\m sai la\ chuye^.n thu+o+\ng ti\nh, ke^? ca?
nhu+~ng ba^.c
thie^n ta\i nha^'t cu~ng pha?i sai nhie^\u la^\n (ve^\ sau anh Thi bo?
toa'n la\m chi'nh tri.,
ddo.an na\y kho^ng ti'nh). Ma(.t kha'c, ca'i o^ng Thi la\m mo+'i me? thu+.c
su+., 
kho^ng copy cu?a ai nha^.n la\ cu?a mi\nh. Nhu+ va^.y, "phe ddo^'i la^.p"
kho^ng 
be? ddu+o+.c o^ng Thi la\ thie^'u trung thu+.c trong khoa ho.c.. O^ng
Tuye^n thi\ kha'c.
Ke^'t qua? ng\ ta dda(ng ba'o tru+o+'c 6,7 na(m vo+ tha\nh cu?a mi\nh thi\
hoa(.c la\
do^'t dde^'n mu+'c kho^ng bie^'t dde^'n su+. to^\n ta.i cu?a ke^'t qua?,
hoa(.c la\ gian la^.n
(Nhu+ng khi o^ng ta du\ng ky' hie^.u cu.a o^ng Hu+ng kho^ng the\m gia?i
thi'ch la\ gi\
thi\ co' gia? thuye^'t la\ vu+a\ na\y vu+a\ no.)


> Thu+.c ra chi? co' va^'n dde^` dda.o ddu+'c va` do ddo' lie^n
> he^. dde^'n chu+'c tu+o+'c, chu+' ba(`ng ca^'p thi` vi. ta^'t
> dda~ ai co' quye^`n thay ddo^?i cho du` co' la^.p ho^.i ddo^`ng
> xe't la.i lua^.n va(n. 

Ba(\ng ca^'p thi\ quan tro.ng gi\ ne^'u su+. nghie^.p ddi ddo+\i

> Lua^.n va(n Tie^'n si~, pho' tie^'n si~ o*? Ta (VN) co' tie^u chua^?n 
>chung cho ca? nu*o*'c kho^ng ? Ne^'u co' thi` nhu* the^' nao` .
> Mong ca'c ba'c chi? gia'o ! To^i la` ngoa.i nga.ch vi` ddu*o*.c dda`o 
>ta.o ngoa`i nu*o*'c, ne^n kho^ng ro~ tie^u chua^?n trong nu*o*'c ra sao 

Theo tui hie^?, he^. tho^'ng o+? VN gio^'ng Ddo^ng A^u cu~, ne^n cu+' ai
ba?o ve^. Candidat
hay Dr. o+? Nga hay Do^ng A^u thi\ ve^\ ddu+o+.c go.i la\ PTS hay TS
tu+o+ng
u+'ng, sau khi pha?i no^.p 1 ba?n lua^.n a'n 
(hi\nh nhu+ pha?i vie^'t la.i ba(\ng tie^'ng Vie^.t?!) cho Thu+ Vie^.n
Quo^'c Gia.
Ne^'u la\ Dr. habil. hay Dr. d'etat thi\ cu~ng go.i la\ TS, nhu+ng ma\ PhD
tu+\
Anh, Me~o,... thi\ cu~ng la\ Dr. (? ca'i na\y hi\nh nhu+ cha? co' lua^.t
cu. the^? vi\
tru+o+'c co' ai PhD o+? Me~o dda^u). Chuye^.n o^ng Tuye^'n kho^ng co\n ba?n
lua^.n a'n o+? Thu+ vie^.n quo^'c gia + o+? nha\ ca\ng la\m ngu+o+\i ta tin
o^ng na\y
gian la^.n.

>Tbilisi(LX cu~) so^' 97 na+m 1992. Ba`i vie^'t cu?a O^ Hu+ng theo  
>quy ca'ch ddie^?m ba'o, bi`nh lua^.n ba'o, go^`m ca'c co^ng ddoa.n  
>sau: To'm ta+'t, nha^.n ddi.nh, dda'nh gia', ne^u le^n ca'c trao  
>ddo^?i KH... To^i dda~ ra xe't ba`i na`y to+'i 20 la^`n dde^? xem  
>co' chu+~ na`o o^ Hu+ng dde^` ca^.p dde^'n LA TS cu?A o^ Tuye^'n hay  
>kho^ng, nhu+ng tuye^.t nhie^n kho^ng tha^'y.

O^ng Bu+?u Nam na\y co' ve? be^nh o^ng Tuye^'n nhi?.
Ta^'t nhie^n la\ review ba\i ba'o thi\ chi? no'i dde^'n ba\i ba'o tho^i
chu+'.
Co' pha?i la\ nha\ va(n dda^u ma\ bi\nh ca'i na\y ra ca'i no.
The^' nhu+ng o^ng Bu+?u Nam co^' ti\nh lo+\ ddi 2 chi tie^'t chi'nh:
nhu+~ng ca^u
vie^'t cu?a o^ng Hu+ng chu+'ng to? o^ng Tuye^n pirate, va\ ba\i ba'o co'
le~ 
la\ co+ so+? cu?a lua^.n a'n. Ne^'u o+? VN kho^ng ti\m ddu+o+.c lua^.n a'n
cu?a
o^ng Tuye^n thi\ to^i nghi~ va\o thu+ vie^.n quo^'c gia o+? LX cu~ va^~n
co\n.

Ho+n nu+~a, ddo^'i vo+'i khoa ho.c thi\ ca'c co^ng tri\nh (the^? hie^.n o+?
dda^y
la\ ca'c ba\i ba'o) quan tro.ng ho+n lua^.n a'n. Lua^.n a'n thi\ chi? va\i
ba ngu+o+\i
ddo.c, co\n ba'o mo+'i in so^' lu+o+.ng lo+'n, co^ng bo^' cho toa\n bo^.
nhu+~ng
ngu+o+\i trong nga\nh bie^'t. Ng\ ta dda'nh gia' 1 ng\ la\m toa'n cu~ng la\
qua nhu+~ng
ba\i ba'o cu?a anh ta, chu+' co' ma^'y ai bie^'t anh ta vie^'t ca'i gi\
trong lua^.n a'n.
NNe^'u ba\i ba'o dda~ la\ ddi pirate cu?a ng\ kha'c, thi\ the^' la\ ddu?

Dde^? tui tra Math. Reviews xem ca'c ba\i ba'o kha'c cu?a o^ng Tuye^n ra
sao.

 
>  Nhu+ va^.y theo to^i, dda^y la` 1 cuo^.c trao ddo^?i, tranh lua^.n  
>KH giu+~a ca'c nha` KH cu`ng chuye^n mo^n sa^u vo+'i nhau. AI  
>ddu'ng, ai sai, gio+'i KH cu`ng chuye^n mo^n sa^u se~ tha^?m ddi.nh.  
>DDie^`u ddo' la` bi`nh thu+o+`ng trong KH.

Pirate ke^'t qua? ng\ kha'c thi\ kho^ng pha?i la\ "bi\nh thu+o+\ng trong
KH"
(tuy ca'i ddo' tho+i\ na\o cu~ng co'). Dda^y kho^ng pha?i la\ trao ddo^?i 
ve^\ khoa ho.c nu+a~ ma\ la\ ve^\ dda.o ddu+'c, nhu+ ba'c Tie^'n vie^'t.

Cheers, Zung