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Homepage da`nh cho chuye^.n cu+o+`i (Do you like joke ?)
Cha`o ta^'t ca? ca'c anh,
To^i ddo.c ta^'t ca? ca'c chuye^.n cu+o+`i cua? anh So dda(ng le^n va`
thu+c su+. ca?m tha^'y bi. cuo^'n hu't, khi ddo.c xong mo^.t chuye^.n
hay thi` cu+o+`i " ga^`n che^'t", khi ddo.c xong he^'t ro^`i thi`
la.i tie^'c ... va` cu+' ddo+.i dde^'n bu+~a sau !!! La^u la^u anh
hi`nh nhu+ ba^.n la.i bo? be^ anh em, dde^? anh em ddo'i ke'm chuye^.n
cu+o+`i, nhu+ng da.o na`y thi` dde^`u ho+n.
To^i co' mo^.t sa'ng kie^'n (to^'i kie^'n) nho? la` co' ne^n la`m
mo^.t homepage hay kho^ng, va` co' anh na`o ra?nh ro^?i mo^.t
chu't la`m webmaster dde^? anh em gu+?i mail dde^'n (theo mo^.t form
nha^'t ddi.nh la` co' the^? ddo.c va`o automatic va referesh page).
Nhu+ va^.y anh em chu+a ddo.c, hay mo+'i va`o sau, hoa.c kho^ng giu+~
la.i ca'c mail cu~ dde^`u co' the^? thu+o+?ng thu+' va` hu+o+'ng
da^~n cho ca'c ba.n be` cu?a mi`nh, ddo^`ng tho+`i ta co' mo^.t bo^.
su+u ta^.p tha^.t thu' vi. va` luo^n fresh ? Anh em nghi~ sao ? To^i
chu+a da'm mo+ u+o+'c mo^.t da.ng nhu+ VNSA Tuo^?i Tre? Cu+o+`i
Homepage, nhu+ng ta.i sao la.i kho^ng the^? ddu+o+.c nhi ?
Mong y' kie^'n cu?a ca'c anh em,
Tha^n a'i,
> Date sent: Mon, 16 Jun 1997 06:49:19 -0500 (CDT)
> Send reply to: vnsa-l@csd.uwm.edu
> From: Tran Cong So <ot003968@bkc.ritsumei.ac.jp>
> To: Multiple recipients of list <vnsa-l@csd.uwm.edu>
> Subject: truyen cuoi
> -----------------------
> Different characters
>
> Ti'nh ca'ch kha'c nhau
> Mo^.t gia'o su+ sinh va^.t ho.c nu+o+'c ngoa`i du+. ddi.nh in mo^.t =
> cuo^'n sa'ch khoa ho.c ve^` loa`i giun ddu~a ta.i nhie^`u nu+o+'c tre^n =
> the^' gio+'i. O^.ng be`n tham kha?o mo^.t ddo^`ng nghie^.p ngu+o+`i =
> Vie^.t Nam, vi` su+. no^?i tie^'ng trong ca'ch dda(.t te^n va` minh hoa. =
> bi`a cho sa'ch o+? nu+o+'c na`y. DDo^`ng nghie^.p cu?a o^ng go'p y':
> - o+? Anh ne^n dda(.t te^n cho sa'ch la`: Ba('t giun - mo^.t mo^n the^? =
> thao thu' vi..
> - o+? Nha^.t dda(.t la`: Suy nghi~ cu?a loa`i giun, giun vo+'i su+. =
> to^`n ta.i cu?a ddo+`i so^'ng con ngu+o+`i.=20
> - o+? DDu+'c dda(.t la`: Nguye^n ta('c so^'ng cu?a loa`i giun ky? =
> lua^.t cu?a chu'ng. =20
> - o+? Italia: Ba('t giun , mo^.t ha`nh ddo^.ng vi pha.m lua^.t ba?o =
> ve^. thie^n nhie^n va` mo^i tru+o+`ng.
> - o+? My~: Kinh doanh giun, mo^.t nghe^` la`m cho ba.n tro+? tha`nh =
> trie^.u phu', co' 3900 loa`i giun trong vu~ tru..
> - o+? Pha'p: Ba.n dda~ bao gio+` ca?m nha^.n ddu+o+.c the^' gio+'i bao =
> la, huye^`n bi' va` chan chu+'a ti`nh ca?m cu?a loa`i giun? =20
> - o+? Trung Quo^'c: Thi.t giun, mo^.t mo'n a(n dda(.c sa?n tuye^.t =
> vo+`i, va` co^ng thu+'c che^' bie^'n thi.t giun.
> Co`n o+? Vie^.t Nam thi` sao? Chu'ng ta ne^n dda(.t te^n gi` cho =
> quye^?n sa'ch co' lo+.i nha^'t mo+`i ca'c ba.n the^m va`o.=20
> SV.TR1@FPT ( st )=20
> =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
> Theo mi`nh ne^n dda(.t la`:
> Giun ddu~a, ngu+o+`i ba.n luo^n o+? be^n ta. =09
> =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
>
> Tu+`: MADONE@FPT
> Gu+?i cho: SV.TR1@FPT
> Tie^u dde^`: Re: Different characters.
>
> Cha`o Sv.tr1 va` ca'c ba.n. Ho^m nay to^i va`o la`ng cu+o+`i va` ddo.c =
> ma^?u chuye^.n different characters cu?a ba.n va` tha^'y no' la` mo^.t =
> sa'ng kie^'n ra^'t hay tuy cu~ng ra^'t ga^`n gu~i vo+'i chu'ng ta. Pha?i =
> ta.i sao chu'ng ta la.i kho^ng mo+? mo^.t Ca^u La.c Bo^. ddo^' vui o+? =
> tre^n lang-cuoi nhi?? Chu'ng ta la` nhu+~ng nha` tho^ng tha'i vui ti'nh =
> ma`, mong ca'c ba.n se~ nhie^.t ti`nh vo+'i y' tu+o+?ng na`y. To^i =
> thu+.c su+. hu+'ng thu' vo+'i y' tu+o+?ng na`y nhu+ng vi` no' la` ly' =
> tu+o+?ng cu?a ba.n, Sv.tr1 tha^n me^'n ne^n ne^'u ba.n thu+.c su+. =
> muo^'n la`m mo^.t ca'i gi` ddo' cho y' tu+o+?ng cu?a anh to^i xin u?ng =
> ho^. anh he^'t mi`nh. Mong thu+ ba.n. =09
> Va` dda^y la` y' kie^'n cu?a to^i ve^` ma^?u chuye^.n ti'nh ca'ch kha'c =
> nhau, theo to^i nghi~ o+? Vie^.t Nam ne^n dda(.t la`: Nuo^i giun mo^.t =
> kie^?u cho+i quy' to^.c kho^ng ke'm Tennis va` dda'nh Golf.
> =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=
> =3D=3D=3D=3D
> Theo to^i co' le~ ngu+o+`i ta se~ dda(.t la`: "Nhu+~ng con giun dda^'t =
> ddi ve^` dda^u?"
> Ha^`u he^'t ca'c pho'ng su+. ngu+o+`i ta dde^`u la^'y te^n "...ddi ve^` =
> dda^u?". Tha^.m chi' dda~ co' "1500 li't su+~a ddo^? xuo^'ng dda^'t ddi =
> ve^` dda^u?"
> Hoa(.c la` "nghe^` nuo^i giun dda^'t, mo^.t nguo^`n lo+.i chu+a ddu+o+.c =
> quan ta^m dda^`u tu+ ddu'ng mu+'c",
> "binh pha'p To^n Tu+? trong vie^.c nuo^i giun",
> "ta^'m gu+o+ng mo^.t ty? phu' cha^n dda^'t, ba('t dda^`u =
> tu+` vie^.c nuo^i giun",
> "thu' nuo^i giun cu?a ngu+o+`i xu+a, mo^.t thu' vui tao =
> nha~",
> "kho^i phu.c va` ba?o to^`n vie^.c nuo^i giun",
> "nuo^i giun, mo^.t ne't dde.p va(n hoa' ca^`n gi`n giu+~",
> "mo^'t nuo^i giun o+? tha`nh thi.",
> "tuo^?i tre? Vie^.t Nam hie^.n nay nghi~ gi` ve^` vie^.c =
> nuo^i giun",
> "ca^`n 20 trie^.u USD dda^`u tu+ cho nuo^i giun o+? Ha` =
> Ti~nh",
> "Ha` No^.i, mu`a...giun dda^'t"
> ....
> va` vo^ kho^'i nhu+~ng dda^`u dde^` kie^?u nhu+ va^.y ma` chu'ng ta =
> va^~n ddo.c ha`ng nga`y.
> ----------------------
>
> ---------------------------
> Mie^.ng ro^.ng
>
> Trong 1 bu+~a tie^.c lie^n hoan sinh nha^.t cu?a mo^.t nu+~ va^.n =
> ddo^.ng vie^n ushu, mo^.t nam nhi xo? xie^n nu+~ thi' chu? ba(`ng mo^.t =
> ca^u tha`nh ngu+~: "DDa`n o^ng mie^.ng ro^.ng thi` sang". Nu+~ thi' chu? =
> ddang ddu+'ng ca.nh ddo' be`n tu'm co^? nam nhi va` dde^` nghi. ddo.c =
> no^'t ca^u co`n la.i cho he^'t y'. Anh cha`ng be`n ca tie^'p ra(`ng: =
> "DDa`n ba` mie^.ng ro^.ng co`n sang ho+n nhie^`u" la`m nu+~ thi' chu? =
> buo^`n cu+o+`i qua' que^n ma^'t vie^.c tru+`ng tri. ke? ho^~n xu+o+.c.
>
> ----------------------
> Tru+` ra
>
> Ca?nh sa't giao tho^ng:
> - DDu+o+`ng na`y qui ddi.nh co' mo^.t chie^`u, sao anh kho^ng tu+. gia'c =
> cha^'p ha`nh?
> Ngu+o+`i ddi xe ma'y:
> - To^i mo+'i ma('c la^`n dda^`u, mong anh tho^ng ca?m.
> Ca?nh sa't giao tho^ng:
> - To^i nho+' ro~ la` dda~ nha('c anh mo^.t la^`n tua^`n tru+o+'c o+? =
> ngay cho^~ na`y.
> Ngu+o+`i ddi xe ma'y:
> - a`, la^`n a^'y to^i ddi xe dda.p.
>
> ---------------------
> Ho.c o+? nha`
>
> La~o chu? qua'n vu+`a dda'nh con vu+`a ma('ng :
> - Ma`y co`n thie^'u tho^'n gi` ma` ddi mo'c tu'i ngu+o+`i ta, bo^i tro =
> tra't tra^'u va`o ma(.t bo^' me. ma`y. Ma`y ho.c o+? dda^u ca'i tho'i =
> a^'y, hu+?.
> - Con ho.c o+? nha`, bo^' a..
> - Sao la.i o+? nha`?
> - Tua^`n tru+o+'c trong khi kie^?m tie^`n, bo^' cha(?ng no'i vo+'i me. =
> ra(`ng tho+`i buo^?i mo'c tu'i nhau, tha(`ng na`o kho^ng mo'c tu'i la` =
> tha(`ng ngu ddo' sao?
> !!!
>
> -------------------------
>
> Doan Hong Nghia