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Plato problem



Hi:
Ho^m tru+o+'c co' ba.n na`o nha('c to+'i vu. xi` xa`o ve^` quye^?n sa'ch
cu?a g/s DDa`o Tro.ng Thi. Theo to^i chuye^.n the^' na`y. G/s Thi co' vie^'t
quye^?n sa'ch vo+'i tha^`y cu?a mi`nh la` vie^.n sy~ Phomenko, ngu+o+`i ra^'t
no^?i tie^'ng (g/s full khi chu+a 30, v/s tho^ng ta^'n khi co`n ra^'t tre?, v/s
cu~ng va^.y). Trong quye^?n sa'ch ddo' ca'c ta'c gia? no'i dda~ gia?i quye^'t
xong Plato problem. Tuy nhie^n, trong Math. Review, reviewer co' comment la`
kho^ng the^? no'i la` gia?i quye^'t xong Plato problem ddu+o+.c vi` ca'c ta'c
gia? ddu+a ve^` ti'nh 1 constant ma` kho^ng the^? ti'nh ddu+o+.c (hay qua'
phu+'c ta.p). Reviewer co' no'i the^m dda.i dde^? la` reviewer tru+o+'c
ddo' dda~ ga(.p Phomenko o+? ho^.i nghi. quo^'c te^' va` dda~ no'i Phomenko
ddie^`u ddo' ma` kho^ng hie^?u sao ca'c ta'c gia? cuo^'n sa'ch va^~n kho^ng 
su+?a.
Theo tui, chuye^.n co' va^.y. Tui ho^?ng co' comment gi`. Ca'c ba.n na`o ddang
la`m to'an cha('c quan ta^m va` ro~ ho+n. La^u nay tui hay ru+?a ba't hoa`i, 
kho^ng co' thi` gio+` la`m toa'n.
T.