Both stacks and queues are like lists (ordered collections of items), but with more restricted operations. They can both be implemented either using an array or using a linked list to hold the actual items.
The conceptual picture of a stack is something like this:
_______ _________ / \ / \ values in \/ / \/ | ----- | values out | | | ----- | | | | ----- | | | | | ----------Think of a stack of newspapers, or trays in a cafeteria. The only item that can be taken out (or even seen) is the most recently added item; a stack is a Last-In-First-Out (LIFO) data structure.
Here are the stack operations:
OPERATION | DESCRIPTION |
Stack() | (constructor) create an empty stack |
boolean empty() | return true iff the stack is empty |
int size() | return the number of items in the stack |
void push(Object ob) | add ob to the top of the stack |
Object pop() | remove and return the item from the top of the stack (error if the stack is empty) |
Object peek() | return the item that is on the top of the stack, but do not remove it (error if the stack is empty) |
The conceptual picture of a queue is something like this:
------------------ values in ----> items in the queue ----> values out ------------------ ^ ^ | | this is the rear of this is the front of the queue the queueThink of people standing in line. A queue is a First-In-First-Out (FIFO) data structure. Items can only be added at the rear of the queue, and the only item that can be removed is the one at the front of the queue.
Here are the queue operations:
OPERATION | DESCRIPTION |
Queue() | (constructor) create an empty queue |
boolean empty() | return true iff the queue is empty |
int size() | return the number of items in the queue |
void enqueue(Object ob) | add ob to the rear of the queue |
Object dequeue() | remove and return the item from the front of the queue (error if the queue is empty) |
The stack ADT is very similar to the list ADT; therefore, their implementations are also quite similar.
Below is the definition of the Stack class, using an array to store the items in the stack; note that we include a static final variable INITSIZE, to be used by the Stack constructor as the initial size of the array (the same thing was done for the List class).
public class Stack { // *** fields *** private static final int INITSIZE = 10; // initial array size private Object[] items; // the items in the stack private int numItems; // the number of items in the stack //*** methods *** // constructor public Stack() { ... } // add items public void push(Object ob) { ... } // remove items public Object pop() throws EmptyStackException { ... } // other methods public Object peek() throws EmptyStackException { ... } public int size() { ... } public boolean empty() { ... } }
Write the Stack constructor.
The push method is like the version of the List add method that adds an object to the end of the list (because items are always pushed onto the top of the stack). Note that it is up to us as the designers of the Stack class to decide which end of the array corresponds to the top of the stack. We could choose always to add items at the beginning of the array, or always to add items at the end of the array. However, it is clearly not a good idea to add items at the beginning of the array since that requires moving all existing items; i.e., that choice would make push be O(N) (where N is the number of items in the stack). If we add items at the end of the array, then push is O(1), except when the array is full.
Here are before and after pictures, illustrating the effects of a call to push:
And here's the code for the push method:
public void push(Object ob) { if (items.length == numItems) expandArray(); items[numItems] = ob; numItems++; }
The pop method needs to remove the top-of-stack item, and return it, as illustrated below.
Note that, in the picture, the value "bbb" is still in items[2]; however, that value is no longer in the stack because numItems is 2 (which means that items[1] is the last item in the stack).
Complete the pop method, using the following header
public Object pop() throws EmptyStackException { }
The peek method is very similar to the pop method, except that it only returns the top-of-stack value without changing the stack. The size method simply returns the value of numItems, and the empty method returns true iff numItems is zero.
Fill in the following table, using Big-O notation to give the worst and average-case times for each of the stack methods for a stack of size N.
OPERATION | WORST-CASE TIME | AVERAGE-CASE TIME |
constructor | ||
empty | ||
size | ||
push | ||
pop | ||
peek |
To implement a stack using a linked list, we must first define the Listnode class. The Listnode definition is the same one we used for the linked-list implementation of the List class.
The signatures of the methods of the Stack class are independent of whether the stack is implemented using an array or using a linked list; only the type of the items field needs to change:
private Listnode items; // pointer to the linked list of items in the stack
As discussed above, an important property of stacks is that items are only pushed and popped at one end (the top of the stack). If we implement a stack using a linked list, we can choose which end of the list corresponds to the top of the stack. It is easiest and most efficient to add and remove items at the front of a linked list, therefore, we will choose the front of the list as the top of the stack (i.e., the items field will be a pointer to the node that contains the top-of-stack item). Below is a picture of a stack represented using a linked list; in this case, items have been pushed in alphabetical order, so "cc" is at the top of the stack:
Notice that, in the picture, the top of stack is to the left (at the front of the list), while for the array implementation, the top of stack was to the right (at the end of the array).
Let's consider how to write the pop method. It will need to perform the following steps:
public Object pop() throws EmptyStackException { if (empty()) throw new EmptyStackException(); // step 1 Object tmp = items.getData(); // step 2(a) items = items.getNext(); // step 2(b) numItems--; // step 3 return tmp; // step 4 }
Now let's consider the push method. Here are before and after pictures, illustrating the effect of a call to push when the stack is implemented using a linked list:
The steps that need to be performed are:
Complete the push method, using the following header.
public void push(Object ob) { }solution
The remaining methods (the constructor, peek, size, and empty) are quite straightforward. You should be able to implement them without any major problems.
Fill in the following table, using Big-O notation to give the worst-case times for each of the stack methods for a stack of size N, assuming a linked-list implementation. Look back at the table you filled in for the array implementation. How do the times compare? What are the advantages and disadvantages of using an array vs using a linked list to implement the Stack class?
OPERATION | WORST-CASE TIME |
constructor | |
empty | |
size | |
push | |
pop | |
peek |
The main difference between a stack and a queue is that a stack is only accessed from the top, while a queue is accessed from both ends (from the rear for adding items, and from the front for removing items). This makes both the array and the linked-list implementation of a queue more complicated than the corresponding stack implementations.
Let's first consider a Queue implementation that is very similar to our (array-based) List implementation. Here's the class definition:
public class Queue { // *** fields *** private static final int INITSIZE = 10; // initial array size private Object[] items; // the items in the queue private int numItems; // the number of items in the queue //*** methods *** // constructor public Queue() { ... } // add items public void enqueue(Object ob) { ... } // remove items public Object dequeue() throws EmptyQueueException { ... } // other methods public int size() { ... } public boolean empty() { ... } }We could implement enqueue by adding the new item at the end of the array and implement dequeue by saving the first item in the array, moving all other items one place to the left, and returning the saved value. The problem with this approach is that, although the enqueue operation is efficient, the dequeue operation is not -- it requires time proportional to the number of items in the queue.
To make both enqueue and dequeue efficient, we need the following insight: There is no reason to force the front of the queue always to be in items[0], we can let it "move up" as items are dequeued. To do this, we need to keep track of the indexes of the items at the front and rear of the queue (so we need to add two new fields to the queue class, frontIndex and rearIndex, both of type int). To illustrate this idea, here is a picture of a queue after some enqueue and dequeue operations have been performed:
Now think about what should happen to this queue if we enqueue two more items: "dd" and "ee". Clearly "dd" should be stored in items[6]. Then what? We could increase the size of the array and put "ee" in items[7], but that would lead to wasted space -- we would never reuse items[0], items[1], or items[2]. In general, the items in the queue would keep "sliding" to the right in the array, causing more and more wasted space at the beginning of the array. A better approach is to let the rear index "wrap around" (in this case, from 6 to 0) as long as there is empty space in the front of the array. Similarly, if after enqueuing "dd" and "ee" we dequeue four items (so that only "ee" is left in the queue), the front index will have to wrap around from 6 to 0. Here's a picture of what happens when we enqueue "dd" and "ee":
Conceptually, the array is a circular array. It may be easier to visualize it as a circle. For example, the array for the final queue shown above could be thought of as:
We still need to think about what should happen if the array is full; we'll consider that case in a minute. Here's the code for the enqueue method, with the "full array" case still to be filled in:
public void enqueue(Object ob) { // check for full array and expand if necessary if (items.length == numItems) { // code missing here } // use auxiliary method to increment rear index with wraparound rearIndex = incrementIndex(rearIndex); // insert new item at rear of queue items[rearIndex] = ob; numItems++; } private int incrementIndex(int index) { if (index == items.length-1) return 0; else return index + 1; }
Note that instead of using incrementIndex we could use the mod operator, and write: rearIndex = (rearIndex + 1) % items.length. However, the mod operator is quite slow, and it is easy to get that expression wrong, so we will use the auxiliary method (with a check for the "wrap-around" case) instead.
To see why we can't simply use expandArray when the array is full, consider the picture shown below.
After calling expandArray, the last item in the queue is still right before the first item -- there is still no place to put the new item (and there is a big gap in the middle of the queue, from items[7] to items[13]). The problem is that expandArray copies the values in the old array into the same positions in the new array. This does not work for the queue implementation; we need to move the "wrapped-around" values to come after the non-wrapped-around values in the new array.
The steps that need to be carried out when the array is full are:
And here's the final code for enqueue:
publc void enqueue(Object ob) { // check for full array and expand if necessary if (items.length == numItems) { Object[] tmp = new Object[items.length*2]; System.arraycopy(items, frontIndex, tmp, frontIndex, items.length-frontIndex); if (frontIndex != 0) { System.arraycopy(items, 0, tmp, items.length, frontIndex); } items = tmp; rearIndex = frontIndex + numItems - 1; } // use auxiliary method to increment rear index with wraparound rearIndex = incrementIndex(rearIndex); // insert new item at rear of queue items[rearIndex] = ob; numItems++; }
The dequeue method will also use method incrementIndex to add one to frontIndex (with wrap-around) before returning the value that was at the front of the queue.
The other queue methods (empty and size) are the same as those methods for the Stack class -- they just use the value of the numItems field.
The first decision in planning the linked-list implementation of the Queue class is which end of the list will correspond to the front of the queue. Recall that items need to be added to the rear of the queue, and removed from the front of the queue. Therefore, we should make our choice based on whether it is easier to add/remove a node from the front/end of a linked list.
If we keep pointers to both the first and last nodes of the list, we can add a node at either end in constant time. However, while we can remove the first node in the list in constant time, removing the last node requires first locating the previous node, which takes time proportional to the length of the list. Therefore, we should choose to make the end of the list be the rear of the queue, and the front of the list be the front of the queue.
The class definition is the same as for the array implementation, except for the fields:
// *** fields *** private Listnode qFront; // pointer to the front of the queue // (the first node in the list) private Listnode qRear; // pointer to the rear of the queue // (the last node in the list) private int numItems; // the number of items in the queue
Here's a picture of a Queue with three items, aa, bb, cc, with aa at the front of the queue:
You should be able to write all of the queue methods, using the code you wrote for the linked-list implementation of the List class as a guide.
The advantages and disadvantages of the two implementations are essentially the same as the advantages and disadvantages in the case of the List class:
Stacks are used to manage methods at runtime (when a method is called, its parameters and local variables are pushed onto a stack; when the method returns, the values are popped from the stack). Many parsing algorithms (used by compilers to determine whether a program is syntactically correct) involve the use of stacks. Stacks can be used to evaluate arithmetic expressions (e.g., by a simple calculator program), and they are also useful for some operations on graphs, a data structure we will learn about later in the semester.
Queues are useful for many simulations, and are also used for some operations on graphs and trees.
Complete method reverseQ, whose header is given below. Method reverseQ should use a Stack to reverse the order of the items in its Queue parameter.
public static void reverseQ(Queue q) { // precondition: q contains x1 x2 ... xN (with x1 at the front) // postcondition: q contains xN ... x2 X1 (with xN at the front) }
public Stack() {
items = new Object[INITSIZE];
numItems = 0;
}
public Object pop() throws EmptyStackException { if (numItems == 0) throw new EmptyStackException(); else { numItems--; return items[numItems]; } }
OPERATION |
WORST-CASE TIME |
AVERAGE-CASE TIME |
constructor |
O(1) |
O(1) |
empty |
O(1) |
O(1) |
size |
O(1) |
O(1) |
push |
O(N) |
O(1) |
pop |
O(1) |
O(1) |
peek |
O(1) |
O(1) |
public void push(Object ob) { items = new Listnode(ob, items); numItems++; }
OPERATION |
WORST-CASE TIME |
constructor |
O(1) |
empty |
O(1) |
size |
O(1) |
push |
O(1) |
pop |
O(1) |
peek |
O(1) |
public static void reverseQ(Queue q) { // precondition: q contains x1 x2 ... xN (with x1 at the front) // postcondition: q contains xN ... x2 X1 (with xN at the front) Stack s = new Stack(); while (!q.empty()) s.push(q.dequeue()); while (!s.empty()) q.enqueue(s.pop()); }