Re: DDa.i, tie^?u thu+`a

["Toan" <toan@usa.net>]

Cha`o ca'c ba'c,

ba'c Tri' ho?i:
> Ai hie^?u the^' na`o la` ca'i KHO^NG trong dda.o /?

Cha`, ba'c ho?i ai hie^?u nghe nga'n qua' vi` ne^'u dda'p thi` ra la`
hie^?u cha(ng?

Tho^i nhu+ va^`y: Hie^?u ti' gi` no'i na^'y chu+' kho^ng la` hie^?u tha^'u
nhe':

Ta, go^`m tha^n, go^`m ta^m, kho^ng co' , vi` ta la` ho+.p cha^'t, ho+.p
nha^n, ho+.p duye^n cu?a ca'c thu+' ma` xu+a go.i la` ddi.a, thu?y, ho?a,
phong, kho^ng pha?i la` cu?a <<ta>>...Nhi`n ca'i duye^n, tho+`i, dem du+.a
va`o no' cho <<ta>> la` ba?n go^'c, la` su+. thu+.c thi` ddo' la` a?o. 

Ta^m cu~ng va^.y, dda^`y nhu+~ng me^ a?o,  vo.ng kie^'n, trong ddo' go^`m :
hi?, no. ai, la.c, a'i , o^' , du.c 
 
Kho^ng cu~ng cha? ha(?n la` kho^ng co', ma` la` co', nhu+ng co' kho^ng
thu+.c.

La^'y Sanh /Die^.t Theo hie^.n tu+o+.ng thi` co' Sanh /die^.t, nhu+ng
thu+.c su+. mo.i thu+' la.i lua^n ho^`i ddi va` la.i, nha^n va` duye^n. 


Tho^i, tui go+.i y' ro^`i xem ca'c ba'c ba`n the^m. Xin lo^~i ba^.n chu+a
xem he^'t ba`i cu?a ca'c ba'c ne^n ra^'t co' the^? dda~ la^.p la.i nhu+~ng
gi` dda~ ban`.

A` ma` co' ba'c na`o no'i dde^'n Nha^n Qua? chu+a he`? Nha^n-Duye^n-Qua?
To^i thi'ch ddu+o+.c xem  Nha^n qua? cu?a Pha^.t gia'o va` cu?a Schrodinger
sa'nh nhau ra sao.

Cheers,
Toa`n