Re: Ta^y vu (correction)

[Tran Minh Tien <tran@idefix.mpipks-dresden.mpg.de>]

> nhu+ "tra`ng" hay "tru+o+`ng" thu+o+`ng ddo.c la^~n cho nhau). The^' nhu+ng
> kho^ng pha?i chu+~ Ha'n chi du` co' bie^?u a^m, bie^?u y' cu~ng ddu+o+.c ca'c cu.
> nha` ta vo+ va`o, nhu+ "chi. = nu+~ + thi.", trong khi chu+~ Ha'n dda~ co'
> "ti? = nu+~ + vi."\. To^i tha^'y hay nha^'t ca'i ma` to^i pha't hie^.n ra la`

Hi,

Ho^m qua ca'c ba'c ho?i ve^` chu+~ "do" la`m to^i pha?i tra tu+. ddie^?n
mo+'i ti`nh co+` pha't hie^.n ra mi`nh nha^`m chu+~ "ti?". O+? tre^n to^i
vie^'t sai, "nu+~ + vi." la` "muo^.i" cho+' kho^ng pha?i "ti?". Xin lo^~i
ca'c ba'c la` nha^.n xe't cu?a to^i ve^` chu+~ "chi.", "ti?" nhu+ va^.y
kho^ng ddu'ng nu+~a\.

Tie^.n dda^y to^i correct luo^n quye^?n "Ha'n va(n tu+. ho.c" cu?a
Nguye^~n Va(n Ba, ba`i "Tha^n thuo^.c" ho. in lo^.n ca'c chu+~ ti?,
muo^.i, ho^n, te^', du, ly' vo+'i nhau\. Ca'c ba'c du`ng quye^?n na`y
ne^n chu' y' ke?o ho.c pha?i ca'i "do+?m" nhu+ to^i\.

Tra^`n Minh Tie^'n



> chu+~ "nho = nha^n + va(n", kha'c chu+~ Ha'n "nho = nha^n + nhu". Cu+' nhu+ to^i
> bie^'t (co' the^? xem ba^'t  cu+' sa'ch na`o gia?ng ve^` Nho gia'o) thi` chu+~
> "nho" Ha'n chi? ngu+o+`i (nha^n) ddu+o+.c dda`o  ta.o, ddang ddo+.i cho+` (nhu)
> dde^? ra la`m vie^.c cho xa~ ho^.i\. Nhi`n chu+~ "nho" No^m thi` ta la.i tha^'y
> ddo' la` chi? ngu+o+`i (nha^n) co' va(n (va(n nha^n). Nhu+ va^.y ca'c cu. nha` ta
> cho ra(`ng Nho gia'o chi? ca^`n dda`o ta.o ngu+o+`i bie^'t va(n tho^i va` the^'
> la` la`m vie^.c cho xa~ ho^.i ddu+o+.c ro^`i\. Co' le~ dda^y la` mo^.t da^~n chu+'ng
> cho tha^'y xa~ ho^.i VN tro.ng va(n dde^'n ddo^. na`o\.
> 
> Tra^`n Minh Tie^'n
> 
>