Re: Ta?n ma.n quanh truye^.n "Tha^`y"

[Dinh Van An <dvan@ena.phys.wani.osaka-u.ac.jp>]

Cha`o ca'c ba'c!
Cha`o Ba'c Tie^'n!
 Ba'c vie^'t hay qua', ddu'ng nhu+ ca?m nha^.n cu?a to^i ve^` truye^.n  
nga+'n na`y co' ddie^`u to^i kho^ng vie^'t hay ddu+o+.c nhu+ ba'c.
>To^i kho^ng the^? gia?i thi'ch tha`nh ngu+~ "ca.n ta`u ra'o ma'ng".
 To^i tha^'y ddu+o+.c ca'i "ca.n ta`u ra'o ma'ng" cu?a ta'c gia? nhu+ ba'c  
Tie^'n no'i o+? ca'i ca^u cuo^'i:
>"Co`n tha^`y\. To^i quay sang: tha^`y dda~ ngu? tu+` bao gio+`, ma+'t  
>hu+o+'ng tha+?ng le^n tra^`n nha`, hai tay ba('t che'o tru+o+'c bu.ng. >Tu+  
the^' ra^'t la` mo^ pha.m...."
 A'c qua'! Ta'c gia? kho^ng dde^? co+ ho^.i cho o^ng Tha^`y tra+n tro+? vi`  
ca'i ha`nh ddo^.ng mu+u sinh cu?a mi`nh. Cu+' nhu+ la` "ca`y xong thu+?a  
ruo^.ng", thanh tha?n va` vo^ tu+. Pha?i cha+ng la` mo^.t su+. tha ho'a nhu+  
ba'c no'i\. Mo^.t ngu+o+`i nhu+ chu'ng ta la`m nhu+ the^' dda~ la` dda'ng  
ddau lo`ng, dda^y la.i la` ca? mo^.t nie^`m ngu+o+~ng mo^. nga`y xu+a cu?a  
ta'c gia?\. Ta'c gia? muo^'n no'i gi` o+? dda^y?
Pha?i cha+ng muo^'n ha`m y' ra+`ng su+. tha ho'a trong y' thu+'c vi` mu+u  
sinh kho^ng chu+`a ca? nhu+~ng tha^`n tu+o+.ng cu?a qua' khu+'?
DDo+`i thu+.c co' the^? bi. ta^`m thu+o+`ng ho'a nhu+ng ca'i "si~" cu?a ke?  
si~ ma^'t ddi thi` O^i! tha^.t la` ddau ddo+'n!
DVAn