[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
truyen cuoi

To: Multiple recipients of list <vnsa-l@csd.uwm.edu>
Subject: truyen cuoi
From: Tran Cong So <ot003968@bkc.ritsumei.ac.jp>
Date: Sat, 3 May 1997 18:51:18 -0500 (CDT)
Reply-To: vnsa-l@csd.uwm.edu
Sender: vnsa-l@csd.uwm.edu


----------
From: 	Viet-Khsv
Sent: 	Saturday, May 3, 1997 8:02 PM
To: 	ot003968@bkc.ritsumei.ac.jp
Subject: 	[Viet-Khsv] Re: VKSVCC  a-d

	=09
Sau le^~ cu+o+'i , vo+. a^u ye^'m ba?o cho^`ng: Anh o+i em ra^'t ye^u =
anh nhu+ng anh hu+'a vo+'i em la` se~ kho^ng bao gio+` ddu.ng va`o ca'i =
ho`m nho? dda(.t dda^`u giu+o+`ng cu?a em kho^ng?
-u+`,anh hu+'a - ngu+o+`i cho^`ng dda'p
sau mu+o+`i na(m chung so^'ng, kho^ng chi.u no^?i su+. to` mo` anh =
cho^`ng mo+? ca'i ho`m nho? ra . Anh ta ra^'t nga.c nhie^n khi tha^'y 2 =
qua? tru+'ng va? 100 ddo^ la . Anh dda`nh mang chuye^.n a^'y ho?i vo+.=20
-Tho^i thi` anh dda~ mo+? ra ro^i ne^n em cu~ng cha(?ng da^'u anh la`m =
gi` nu+~a. Trong nhu+~ng na(m qua , mo^~i la^`n em ddi la(ng nha(ng =
vo+'i mo^.t ngu+o+`i dda`n o^ng em la.i dda(.t mo^.t qua? tru+'ng va`o =
dda^'y.- ngu+o+`i vo+. no'i
-.Em xinh dde.p la` va^.y ma` trong vo`ng 10 na(m la(ng nha(ng co' 2 =
la^`n thi` anh cu~ng  tha thu+' ddu+o+.c. The^' nhu+ng 100 ddo^ la la` =
gi`?
- Anh co' hie^?u kho^ng. Nhu+ng mo^~i  la^`n tru+'ng dda^`y ho`m em =
pha?i mang tru+'ng ddi ba'n ne^n dde^'n ba^y gio+` mo+'i co' 100 ddo^ =
a^'y!!!
Cho^`ng !!??
				He^'t

Hy vo.ng ca'c ba.n se~ ra^'t thi'ch chuye^.n na`y ve^` ca'i ke^'t cu.c =
ba^'t ngo+` cu?a no'. Ha~y Repl hoa(.c bo^? sung va`o series chuye^.n =
ngoa.i ti`nh na`y
---------------------------------

Sau le^~ cu+o+'i , vo+. a^u ye^'m ba?o cho^`ng: Anh o+i em ra^'t ye^u =
anh nhu+ng anh hu+'a vo+'i em la` se~ kho^ng ddi la(ng nha(ng vo+'i =
ai.Co`n ne^'u mo^~i la^`n Anh ddi vo+'i ai thi` se~ bo? va`o chie^'c =
ho^.p cu?a Anh mo^.t ha.t ddo^~ ,va` Em cu~ng va^.y.
   Sau ra^'t nhie^`u na(m chung so^'ng mo^.t nga`y kia ngu+o+`i cho^`ng =
bi. o^'m na(.ng sa('p qua ddo+`i Anh ta no'i vo+'i vo+. mang hai chie^'c =
ho^.p kia ra.
  Sau khi ddo^? hai chie^'c ho^.p ra ngu+o+`i cho^`ng su+~ng so+` khi =
tha^'y trong chie^'c ho^.p cu?a mi`nh co' qua' nhie^`u ha.t ddo^~.Anh ta =
no'i vo+'i vo+.:
    Anh ra^'t buo^`n vi` Anh dda~ ddi la(ng nha(ng qua' nhie^`u Ha~y tha =
lo^~i cho anh vi` gio+` dda^y Anh kho^ng co`n so^'ng ddu+o+.c bao la^u.
  Ngu+o+`i vo+. no'i:
     Em mo+'i la` ngu+o+`i co' lo^~i vi` bie^'t Anh thi'ch a(n canh =
ddo^~ ne^n ho^m qua Em dda~ ddo^? mo^.t i't ddo^~ trong chie^'c ho^.p =
cu?a Em ra dde^? na^'u cho Anh a(n. =20
  Cho^`ng............


---------------------------------
=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D
Co' mo^.t ddo^i vo+. cho^`ng tre? quye^'t ddi.nh tie^'t kie^.m tie^`n =
ba(`ng ca'ch sau mo^~i la^`n ..."ye^u nhau " o^ng cho^`ng pha?i bo? va`o =
con lo+.n dda^'t mo^.t to+` mu+o+`i nghi`n ddo^`ng.Sau mu+o+`i na(m ho. =
quye^'t ddi.nh bo^? con lo+.n dda^'t ra.Ho. dda~ co' mo^.t so^' tie^`n =
kha' lo+'n song co' mo^.t ddie^`u la` pha^n nu+?a so^' tie^`n la.i la` =
nhu+~ng to+` 50.000 dd.Anh  cho^`ng ra^'t la^'y la`m nga.c nhie^n be`n =
ho?i vo+. chuye^.n ddo'.Chi. vo+. thu?ng tha(?ng dda'p:
"Ta.i vi` o^ng ha`ng xo'm kho^ng co' tie^`n le? ."

--------------------------------
Ha.t ke^

    Pho`ng kha'm be^.nh ta^m tha^`n

    Mo^.t ngu+o+`i dda`n o^ng cu+' tu+o+?ng mi`nh la` "ha.t ke^". Kho^ng =
bao gio+` anh da'm ra ngoa`i sa^n, anh chi? so+. lu~ ga` mo^? mi`nh a(n =
thi.t. DDu+o+.c ba.n be` gio+'i thie^.u anh dde^'n ba'c sy~ chu+~a =
be^.nh.. Sau mo^.t tho+`i gian chu+~a cha.y ba'c sy~ pho?ng va^'n:
	- The^' na`o anh co`n ca?m tu+o+?ng mi`nh la` "ha.t ke^" nu+~a kho^ng?
	- Kho^ng, to^i kho^ng he^`, nhu+ng chi? so+. lu~ ga` la.i kho^ng nghi~ =
the^'.

---------------------------------
Nga`y tru+o+'c a^'y ca'c ba'c a., KTX sinh vie^n no' te^. ho+n ba^y =
gio+` nhie^`u. Toilet la` nam nu+~ chung nhau. Ai muo^'n ddi pha?i xe^'p =
ha`ng. Ai kho^ng muo^'n xe^'p ha`ng thi` ra ngoa`i tro+`i ma` release =
ca'i no^~i buo^`n cu?a mi`nh.
Ho^m ddo', tro+`i la.i mu+a to. Co' anh cha`ng sau ma^'y pha sa't pha.t =
vo+'i ba.n be`, mo't qua', cha.y xuo^'ng toilet thi` tha^'y cu+?a ddo'ng =
im i?m ro~ la` co' ke? ddang chie^'m ddo'ng. Anh cha`ng he't le^n:
 -- Mo+? cu+?a cho tao va`o ca'i
Be^n trong im la(.ng nhu+ to+`.
 -- Me. kie^'p, co' mo+? kho^ng? Kho^ng tao dda.p cu+?a va`o dda^y na`y.
Pha?i ma^'y phu't sau, cu+?a mo+'i mo+?. Mo^.t co^ na`ng vu+`a bu+o+'c =
ra vu+`a xo^'c la.i qua^`n, mie^.ng da^?u le^n:
 -- DDo^` vo^ duye^n, con ga'i ngu+o+`i ta ddang i. ma` cu+' go.i do'ng =
le^n the^' a`.

---------------------------------
	Mo^.t buo^?i le^n lo+'p.
	Co^ gia'o:
		Ha^`u nhu+ chu'ng ta dde^`u dda'nh va^`n sai tu+` "so+` na(.ng" va` =
"so+` nhe.".
So+` na(.ng la` (Co^ gia'o vie^'t le^n ba?ng) "S", co`n so+` nhe. la` =
"X", nhu+ va^.y chu'ng ta tha^'y so+` na(.ng "S" co' "mo?" gio^'ng mo? =
con chim, co`n so+` nhe. "X" gio^'ng hi`nh con bu+o+'m va^.y ca'c em =
pha?i nho+' ky~ dde^? khi vie^'t kho^ng sai lo^~i chi'nh ta?! Ba^y gio+` =
em ha~y ne^u mo^.t vi' du. dde^? pha^n bie^.t chu+' "so+` na(.ng" va` =
"so+` nhe."? (Co^ gia'o chi? mo^.t ca^.u ho.c sinh tu+o+ng ddo^'i tho^ng =
minh).
	Ho.c sinh:
		(Nga^~m nghi~ mo^.t lu'c) DDa'p: Thu+a co^! So+` "Sung su+o+'ng" go.i =
la` so+` chim va` So+` "Xa^'u xa" la` so+` bu+o+'m a.!
	Co^ gia'o: Ha?...????

---------------------------------
Mo^.t chu' bi. nghe^~nh nga~ng va'c ca^`n ca^u ddi ddu+o+`ng ga(.p mo^.t =
chu' kha'c cu~ng bi. nga~ng tai kho^ng ke'm. Sau dda^y la` ma^?u ddo^'i =
thoa.i giu+~a ho.:
Chu' kia ho?i: 	Anh ddi ca^u dda^'y a` ?
Chu' ca^`m ca^`n ca^u: 	To^i ddi ca^u dda^'y chu+' !
Chu' kia tha('c ma('c:	The^' anh kho^ng ddi ca^u thi` ca^`m ca^`n ca^u =
theo la`m gi` ?
.....!

--------------------------------
Mo^.t phu. nu+~ da'm ta^'n co^ng la.i 1 te^n tro^.m va`o nha` ba` va`o =
lu'c 2 gio+` sa'ng. Sa'ng ho^m sau, ba'o chi' ddi.a phu+o+ng dde^'n =
pho?ng va^'n ba` ve^` ha`nh ddo^.ng du~ng ca?m ddo', ba` ta bi`nh tha?n =
tra? lo+`i: " co' gi` dda^u, to^i tu+o+?ng dda^'y la` la~o cho^`ng nha` =
to^i ddi nha^.u ve^` khuya! "
     =20
-------------------------------
Chie^'c xe ca't

Pho`ng tri. lie^.u ta^m ly'

       Mo^.t ngu+o+`i dda`n o^ng than phie^`n vo+'i ba'c sy~

	- Thu+a ba'c sy~, Ma^'y dde^m ga^`n dda^y to^i me^.t mo?i kho^ng the^? =
chi.u ddu+.ng ddu+o+.c.
	- Co^ng vie^.c cu?a anh na(.ng ne^` qua' sao. To^i khuye^n anh ne^n bo? =
bo+'t tho+`i gian dde^? nghi? ngo+i.
	- Thu+a ba'c sy~, kho^ng pha?i va^.y. Cu+' mo^~i dde^m khi ngu? to^i =
la.i tha^'y mo^.t ngu+o+`i dde^'n ba('t to^i ke'o mo^.t chie^'c xe ca't =
ra ti't dda^`u tha`nh pho^' dde^'n ta^.n sa'ng mo+'i ti?nh da^.y, =
ngu+o+`i me^.t nhoa`i.
	- The^' thi` khi na`o anh ta dde^'n anh cu+' ba?o anh ta dde^'n cho^~ =
to^i.
	- Ca'm o+n ba'c sy~.

       Nga`y ho^m sau ngu+o+`i dda`n o^ng na`y la.i ti`m dde^'n ba'c =
sy~.

	- Ca'm o+n ba'c sy~. To^i dda~ ba?o vo+'i anh ta nhu+ ba'c sy~ da(.n, =
anh ta kho^ng qua^'y ra^`y to^i nu+~a.

       Nga`y ho^m sau nu+~a, anh ta la.i xua^'t hie^.n.=20

	- Ba'c sy~ giu'p to^i vo+'i. Ba^y gio+` anh ta kho^ng dde^'n nu+~a. =
Nhu+ng cu+' mo^~i khi to^i ngu? la.i me^ tha^'y co' dde^'n 3 co^ ga'i =
ba('t to^i chie^`u chuo^.ng, la`m ti`nh. To^i kho^ng co`n chi.u no^?i =
nu+~a.
	- Ne^'u ho. dde^'n anh cu+' ba?o mo^.t co^ sang cho^~ to^i.
	- The^' sao kho^ng ba?o hai co^, hay la` ca? ba ddi a..
	- Kho^ng ddu+o+.c! Ba^y gio+` dde^m na`o to^i cu~ng co`n ba^.n ke'o =
chie^'c xe ca't dde^'n sa'ng.

------------------------------------
Prev by Date: [Ba'o VN] Chuye^?n giao co^ng nghe^.
Next by Date: [Chess] Kasparov beats Deep Blue in game one!!!
Prev by thread: [Ba'o VN] Chuye^?n giao co^ng nghe^.
Next by thread: truyen cuoi
Index(es):
- Date
- Thread