[0, 0]
to [1, 1]
with the unit parameter u
between 0 and 1? [u, u]
[u2, u2]
[2 * u, 2 * u]
[u, u2]
[Math.sin(u), Math.sin(u)]
u = 0
than u = 1
)? Do not include the ones with constant speed. [-u2, 0]
has speed 0
at the beginning and -2
as the end, and technically -2
is "faster" than 0
, so the answer is incorrect. [Math.sqrt(u), 0]
[Math.log(1 + u), 0]
[-u2, 0]
[u2, 0]
[-u, 0]
[a * (1 - u) + b * u, 0]
where u
is the unit parameter from 0 to 1? Choose the ones that work for any values of a
and b
. [b * (1 - u) + a * u, 0]
[a + (b - a) * u, 0]
[b + (a - b) * u, 0]
[a + b * u, 0]
[a + b * (1 - u), 0]
[1 + 2 * u + 3 * u2, u]
? [1, 0]
[6, 1]
[6, 0]
[1, 1]
[3, 1]
[1 + u2, u]
at [1, 0]
? [0, 1]
[2, 1]
[2, 0]
[0, 0]
[1, 0]
u = 0.5
from the De Casteljau construction of the quadratic Bezier curve with endpoints [0, 0]
, [1, 1]
and the middle control point [1, 0]
? [0.75, 0.25]
[0.5, 0]
[1, 0.5]
[0.25, 0.75]
[0.5, 0.5]
[0, 0]
, [1, 1]
and derivative [0, 1]
at the first point, which three of the following points are the control points of the Bezier curve? [0, 0], [0, 0.5], [1, 1]
. [0, 0]
[1, 1]
[0, 0.5]
[0, 1]
[0, 2]
[0, 0]
, [1, 1]
and derivatives at those points [0, 1]
and [1, 0]
respectively, which two of the following points are the second and third control points of the Bezier curve? [0, 1/3], [2/3, 1]
. [0, 1/3]
[2/3, 1]
[4/3, 0]
[0, 3]
[-2, 1]
Last Updated: November 30, 2024 at 4:35 AM