let shape = new THREE.Shape();
, a 2D shape, as a parameter? THREE.ShapeGeometry(shape)
THREE.ExtrudeGeometry(shape)
THREE.LatheGeometry(shape)
THREE.TubeGeometry(shape)
THREE.BufferGeometry(shape)
cube = new THREE.Mesh(...);
that is moving along a curve = new THREE.Curve();
and is current at curve.getPoint(t)
so that it is facing the direction it is moving, where should the cube look at (what is the point p
in cube.lookAt(p)
)? cube.position.add(curve.getTangent(t))
curve.getPoint(t).add(curve.getTangent(t))
curve.getPointAt(t).add(curve.getTangentAt(t))
curve.getTangentAt(t)
curve.getTangent(t)
u = 0
to u = 1
and v = 0
to v = 1
? Do not include 3D curves as 3D surfaces. [u, u, v]
[u, u + v, v]
[u, u, u]
[u, v]
[u, u]
[0, 0, 0], [0, 1, 0], [0, 0, 1]
(in this order)? Use the right-hand rule. [-1, 0, 0]
[1, 0, 0]
[0, 0, 0]
[0, 1, 1]
[0, -1, -1]
normalMap
bumpMap
envMap
emissiveMap
displacementMap
[0, 0], [0, 1], [1, 0]
(in this order), where is the point with Barycentric coordinate [0.5, 0.5, 0]
? [0, 0.5]
[0.5, 0]
[0, 0]
[0, 1]
[1, 0]
[0, 0], [0, 1], [1, 0]
(in this order), what is the Barycentric coordinate of [1, 0]
? [0, 0, 1]
[0, 1, 0]
[1, 0, 0]
[1, 0]
[0, 1]
THREE.Texture.minFilter
use tri-linear interpolation to find the color of the pixel on a triangle? THREE.LinearMipmapLinearFilter
THREE.NearestMipmapLinearFilter
THREE.NearestMipmapNearestFilter
THREE.LinearMipmapNearestFilter
THREE.LinearFilter
Last Updated: November 30, 2024 at 4:35 AM