[0, 0] to [1, 1] with the unit parameter u between 0 and 1? [u, u] [u2, u2] [2 * u, 2 * u] [u, u2] [Math.sin(u), Math.sin(u)] u = 0 than u = 1)? Do not include the ones with constant speed. [-u2, 0] has speed 0 at the beginning and -2 as the end, and technically -2 is "faster" than 0, so the answer is incorrect. [Math.sqrt(u), 0] [Math.log(1 + u), 0] [-u2, 0] [u2, 0] [-u, 0] [a * (1 - u) + b * u, 0] where u is the unit parameter from 0 to 1? Choose the ones that work for any values of a and b. [b * (1 - u) + a * u, 0] [a + (b - a) * u, 0] [b + (a - b) * u, 0] [a + b * u, 0] [a + b * (1 - u), 0] [1 + 2 * u + 3 * u2, u]? [1, 0] [6, 1] [6, 0] [1, 1] [3, 1] [1 + u2, u] at [1, 0]? [0, 1] [2, 1] [2, 0] [0, 0] [1, 0] u = 0.5 from the De Casteljau construction of the quadratic Bezier curve with endpoints [0, 0], [1, 1] and the middle control point [1, 0]? [0.75, 0.25] [0.5, 0] [1, 0.5] [0.25, 0.75] [0.5, 0.5] [0, 0], [1, 1] and derivative [0, 1] at the first point, which three of the following points are the control points of the Bezier curve? [0, 0], [0, 0.5], [1, 1]. [0, 0] [1, 1] [0, 0.5] [0, 1] [0, 2] [0, 0], [1, 1] and derivatives at those points [0, 1] and [1, 0] respectively, which two of the following points are the second and third control points of the Bezier curve? [0, 1/3], [2/3, 1]. [0, 1/3] [2/3, 1] [4/3, 0] [0, 3] [-2, 1] Last Updated: September 11, 2025 at 10:55 PM