let shape = new THREE.Shape();, a 2D shape, as a parameter? THREE.ShapeGeometry(shape) THREE.ExtrudeGeometry(shape) THREE.LatheGeometry(shape) THREE.TubeGeometry(shape) THREE.BufferGeometry(shape) cube = new THREE.Mesh(...); that is moving along a curve = new THREE.Curve(); and is current at curve.getPoint(t) so that it is facing the direction it is moving, where should the cube look at (what is the point p in cube.lookAt(p))? cube.position.add(curve.getTangent(t)) curve.getPoint(t).add(curve.getTangent(t)) curve.getPointAt(t).add(curve.getTangentAt(t)) curve.getTangentAt(t) curve.getTangent(t) u = 0 to u = 1 and v = 0 to v = 1? Do not include 3D curves as 3D surfaces. [u, u, v] [u, u + v, v] [u, u, u] [u, v] [u, u] [0, 0, 0], [0, 1, 0], [0, 0, 1] (in this order)? Use the right-hand rule. [-1, 0, 0] [1, 0, 0] [0, 0, 0] [0, 1, 1] [0, -1, -1] normalMap bumpMap envMap emissiveMap displacementMap [0, 0], [0, 1], [1, 0] (in this order), where is the point with Barycentric coordinate [0.5, 0.5, 0]? [0, 0.5] [0.5, 0] [0, 0] [0, 1] [1, 0] [0, 0], [0, 1], [1, 0] (in this order), what is the Barycentric coordinate of [1, 0]? [0, 0, 1] [0, 1, 0] [1, 0, 0] [1, 0] [0, 1] THREE.Texture.minFilter use tri-linear interpolation to find the color of the pixel on a triangle? THREE.LinearMipmapLinearFilter THREE.NearestMipmapLinearFilter THREE.NearestMipmapNearestFilter THREE.LinearMipmapNearestFilter THREE.LinearFilter Last Updated: September 11, 2025 at 10:55 PM